Since HOPE is a parallelogram, therefore, HE∥OP and
HO∥EP
Now, HE∥OP and transversal HO intersects them.
∴∠EHO=∠POX[∵ Corresponding angles are equal]
∠40∘+z=70∘⇒z=70∘−40∘=30∘
Again, HE∥OP and transversal HP intersects them.
∴∠OPH=∠EHP[∵ Alternate angles are equal)
⇒y=40∘
Since opposite angles are equal in a parallelogram.
∴∠HEP=∠HOP
⇒x=180∘−∠POX=180∘−70∘=110∘
Hence, x=110∘,y=40∘ and z=30∘