CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The adjacent sides of a rectangle with given perimeter as 100 cm and enclosing maximum area are

A
10 cm and 40 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20 cm and 30 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25 cm and 25 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
15 cm and 35 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 25 cm and 25 cm
Let x and y be the adjacent sides of the rectangle.

perimeter of the rectangle =100cm

2(x+y)=100

(x+y)=50

Area of the rectangle =x×y

A=x(50x)

A=50xx2

for maximum area,dAdx=0

502x=0

2x=50

x=25

y=50x

y=5025

y=25

The adjacent sides of a rectangle enclosing maximum area are 25cm and 25cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon