Question

The adjoining diagram shows three soap bubbles $A,$ $B$ and $C$ prepared by blowing the capillary tube fitted with stop cocks, $S_1$ $S_2$ and $S_3.$ With stop cock $S$ closed and stop cocks $S_1,$ $S_2$ and $S_3$ opened

• A. $C$ and $A$ both will start collapsing with the volume of $B$ increasing.
• B. $C$ will start collapsing
  with volumes of $A$ and
  $B$ increasing.
• C. Volumes of $A,$ $B$ and $C$ will become equal at equilibrium.
• D. $B$ will start collapsing
  with volumes of $A$ and
  $C$ increasing.
  

Answer 1

The correct option is A $C$ and $A$ both will start collapsing with the volume of $B$ increasing.

As we know, excess pressure inside a soap bubble is inversely proportional to radius of bubble.

Or $\Delta P\propto \frac{1}{r}$

Therefore, if value of radius increases, the pressure will decrease.
Hence, bubble $A$ and $C$ will posses more pressure than $B$ and air will flow from them to $B.$

Final answer: $\left(c\right)$