The adjoining figure shows a racing track consisting f two parallel stretches $119 m$ long and $10 m$ wide. Its other two ends are semicircle. The inner distance between the two parallel stretches is $70 m$ . Evaluate
The distance around the track along its outer edge.

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Solution

Radius of exterior $= (70 + 10) m = 80 m$
Circumference $= 2 π r = 2 \times \frac{22}{7} \times 80 = \frac{3520}{7} m$
Distance around track
$\frac{3520}{7} + (119 \times 2)$
$\Rightarrow \frac{5186}{7}$
$\Rightarrow 740.86$

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Question 8 (i)
Fig. 12.26 depicts a racing track whose left and right ends are semi-circular.
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(i) The distance around the track along its inner edge

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The adjoining figure shows a racing track consisting f two parallel stretches 119 m long and 10 m wide. Its other two ends are semicircle. The inner distance between the two parallel stretches is 70 m. EvaluateThe distance around the track along its outer edge.

Radius of exterior =(70+10)m=80mCircumference =2πr=2×227×80=35207mDistance around track 35207+(119×2)⇒51867⇒740.86

The adjoining figure shows a racing track consisting f two parallel stretches $119 m$ long and $10 m$ wide. Its other two ends are semicircle. The inner distance between the two parallel stretches is $70 m$ . Evaluate
The distance around the track along its outer edge.

Radius of exterior $= (70 + 10) m = 80 m$
Circumference $= 2 π r = 2 \times \frac{22}{7} \times 80 = \frac{3520}{7} m$
Distance around track
$\frac{3520}{7} + (119 \times 2)$
$\Rightarrow \frac{5186}{7}$
$\Rightarrow 740.86$