wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

The adjoining figure shows a trapezium ABCD in which side AB is parallel to side DC. P and Q are mid - points of diagonals AC and BD respectively. CQ joined and produced meets AB at point R.
Which of the following options are correct?

A
PQ is parallel to AB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
PQ = 12(AB - DC)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Both (a) and (b)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Neither (a) nor (b)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Both (a) and (b)
By ASA, ΔCDQΔRBQ
CQ = QR and DC = RB
(i) In Δ ACR, P is mid-point of AC and Q is mid-point of RC
PQ || AR PQ || AB
(ii) In Δ ACR, P is mid-point of AC and Q is mid-point of CR
PQ=12 AR=12(ABRB)
=12(ABDC)[ RB=DC].

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Triangles between same parallels
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon