1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The adjoining figure shows a trapezium ABCD in which side AB is parallel to side DC. P and Q are mid - points of diagonals AC and BD respectively. CQ joined and produced meets AB at point R. Which of the following options are correct?

A
PQ is parallel to AB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
PQ = 12(AB - DC)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Both (a) and (b)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Neither (a) nor (b)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C Both (a) and (b)By ASA, ΔCDQ≡ΔRBQ ⇒ CQ = QR and DC = RB (i) In Δ ACR, P is mid-point of AC and Q is mid-point of RC ⇒ PQ || AR ⇒ PQ || AB (ii) In Δ ACR, P is mid-point of AC and Q is mid-point of CR ⇒PQ=12 AR=12(AB−RB) =12(AB−DC)[∴ RB=DC].

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Triangles between same parallels
MATHEMATICS
Watch in App
Join BYJU'S Learning Program