The adjoining figure shows the cross-section of a concrete wall to be constructed. It is $1.9$ m wide at the bottom, $90$ cm wide at the top, and $5$ m high. If its length is $20$ m, find the cross-sectional area.

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Solution

REF.Image
Area of crossection = $A_{1} + A_{2}$
$A_{1} = 0.9 \times 5$
$= 4.5 m^{2}$
$A_{2} = \frac{1}{2} (1) \times 5 = 2.5 m^{2}$
Area of crossection = $7 m^{2}$

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The adjoining figure shows the cross-section of a concrete wall to be constructed. It is 1.9m wide at the bottom, 90cm wide at the top, and 5 m high. If its length is 20m, find the cross-sectional area.

REF.ImageArea of crossection = A1+A2A1=0.9×5=4.5m2A2=12(1)×5=2.5m2Area of crossection = 7m2

The adjoining figure shows the cross-section of a concrete wall to be constructed. It is $1.9$ m wide at the bottom, $90$ cm wide at the top, and $5$ m high. If its length is $20$ m, find the cross-sectional area.

REF.Image
Area of crossection = $A_{1} + A_{2}$
$A_{1} = 0.9 \times 5$
$= 4.5 m^{2}$
$A_{2} = \frac{1}{2} (1) \times 5 = 2.5 m^{2}$
Area of crossection = $7 m^{2}$