The age (in years) of $150$ patients getting medical treatment in a hospital in a month are given below. Obtain its mode.
Age (yrs) $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $50 - 60$ $60 - 70$
No. of patients $12$ $14$ $36$ $50$ $20$ $18$

Open in App

Solution

Highest frequency=highest number of patients $= 50$
Therefore, modal class $= 40 - 50$
$l = 40; h = 10; f_{m} = 50; f_{m - 1} = 36; f_{m + 1} = 20$
mode $= L + \frac{f_{m} - f_{m - 1}}{2 f_{m} - f_{m - 1} - f_{m + 1}} \times n$
$= 40 + \frac{14}{14 + 30} \times 10$
$= 43.18$
$\approx 43.2$ years

Suggest Corrections

Similar questions

Age (in years)	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$
No. of patients	$60$	$42$	$55$	$70$	$53$	$20$

The following table shows ages of

300

patients getting medical treatment in a hospital on a particular day. Find the median.

Q. Following are the ages of 360 patients getting medical treatment in a hospital on a day:

Age (in years):	10-20	20-30	30-40	40-50	50-60	60-70
No.of Patients:	90	50	60	80	50	30

Construct a cumulative frequency distribution.

Q. The following table shows the ages of 300 patients getting medical treatment in a hospital on a particular day.

Age (in years)	10-20	20-30	30-40	40-50	50-60	60-70
No. of patients	60	42	55	70	53	20

Find the median age of the patients.

Q. Following are the ages (in years) of 360 patients, getting medical treatment in a hospital:

Ages (in years)	10−20	20−30	30−40	40−50	50−60	60−70
Number of patients	90	50	60	80	50	30

Construct the cumulative frequency table for the above data.

Following are the ages (in years) of 360 patients, getting medical treatment in a hospital:
$\begin{matrix} Age (in years) & 10 - 20 & 20 - 30 & 30 - 40 & 40 - 50 & 50 - 60 & 60 - 70 Numbr of patients & 90 & 50 & 60 & 80 & 50 & 30 \end{matrix}$
Construct the cumulative frequency table for the above data.

Join BYJU'S Learning Program

Age (yrs)	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$
No. of patients	$12$	$14$	$36$	$50$	$20$	$18$

The age (in years) of 150 patients getting medical treatment in a hospital in a month are given below. Obtain its mode.Age (yrs)10−2020−3030−4040−5050−6060−70No. of patients121436502018

Highest frequency=highest number of patients=50Therefore, modal class=40−50l=40;h=10;fm=50;fm−1=36;fm+1=20mode=L+fm−fm−12fm−fm−1−fm+1×n=40+1414+30×10=43.18≈43.2 years

The age (in years) of $150$ patients getting medical treatment in a hospital in a month are given below. Obtain its mode.
Age (yrs) $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $50 - 60$ $60 - 70$
No. of patients $12$ $14$ $36$ $50$ $20$ $18$

Highest frequency=highest number of patients $= 50$
Therefore, modal class $= 40 - 50$
$l = 40; h = 10; f_{m} = 50; f_{m - 1} = 36; f_{m + 1} = 20$
mode $= L + \frac{f_{m} - f_{m - 1}}{2 f_{m} - f_{m - 1} - f_{m + 1}} \times n$
$= 40 + \frac{14}{14 + 30} \times 10$
$= 43.18$
$\approx 43.2$ years