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Question
The age of a father 10 years ago was thrice the age of his son. Ten years later, the father's age will be twice that of his son. The ratio of their present ages is
The age of a father 10 years ago was thrice the age of his son. Ten years later, the father's age will be twice that of his son. The ratio of their present ages is
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Solution
The correct option is C 7:3
Let Son's age = S
Father's age = F
then, F−10=3(S−10)
F=3S−20
and, F+10=2(S+10)
F=2S+10
Thus, 3S−20=2S+10
S=30 years
Hence, F=70 years
Hence required ratio = 7:3
Let Son's age = S
Father's age = F
then, F−10=3(S−10)
F=3S−20
and, F+10=2(S+10)
F=2S+10
Thus, 3S−20=2S+10
S=30 years
Hence, F=70 years
Hence required ratio = 7:3
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