The age of a man is the square of his son's age. A year ago, the man's age was $8$ times the age of his son. What is the present age of the man?

47 y r

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49 y r

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36 y r

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48 y r

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Solution

The correct option is A $49 y r$
let present age of son be $x$
present age of father be $x^{2}$
$1$ year ago
age of son $= x - 1$
age of father = $x^{2}$ -1
so
$x^{2} - 1 = 8 (x - 1)$
$x^{2} - 8 x + 7 = 0$
$(x - 7) (x - 1) = 0$
$x = 7$
son's age $= 7 y e a r s$
man's age = $x^{2} = 49$ years

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The age of a man is the square of his son's age. A year ago, the man's age was 8 times the age of his son. What is the present age of the man?

The correct option is A 49 yrlet present age of son be xpresent age of father be x21 year agoage of son =x−1age of father = x2-1so x2−1=8(x−1)x2−8x+7=0(x−7)(x−1)=0x=7son's age =7yearsman's age = x2=49 years

The age of a man is the square of his son's age. A year ago, the man's age was $8$ times the age of his son. What is the present age of the man?

The correct option is A $49 y r$
let present age of son be $x$
present age of father be $x^{2}$
$1$ year ago
age of son $= x - 1$
age of father = $x^{2}$ -1
so
$x^{2} - 1 = 8 (x - 1)$
$x^{2} - 8 x + 7 = 0$
$(x - 7) (x - 1) = 0$
$x = 7$
son's age $= 7 y e a r s$
man's age = $x^{2} = 49$ years