The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is

5:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7:3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13:4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
7:3

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x+ 10) + 10 = 2[(x+ 10) + 10]

3x+ 20 = 2x+ 40

x= 20.

Required ratio = (3x+ 10) : (x+ 10) = 70 : 30 = 7 : 3

Suggest Corrections

Similar questions

Q. The age of a father

10

years ago was thrice the age of his son.

10

years hence, the father's age will be twice that of his son. The ratio of their present ages is

The age of Xavier 10 years ago was thrice the age of his son. Ten years hence, the man's age will be twice that of his son. The present age of Xavier is:

Q. Five years ago, the age of a father was thrice the age of his son. In five years time, the age of the father will be twice the age of his son at that time. Find their present ages.

Q. Five years hence the age of father will be thrice the age of his son. Two years ago father's age was four times his son's age. Find the sum of their present ages (in years).

Q. Two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their presents ages.

Join BYJU'S Learning Program

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is

The correct option is B 7:3 Let the ages of father and son 10 years ago be 3x and x years respectively. Then, (3x+ 10) + 10 = 2[(x+ 10) + 10] 3x+ 20 = 2x+ 40 x= 20. Required ratio = (3x+ 10) : (x+ 10) = 70 : 30 = 7 : 3

The correct option is B
7:3

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x+ 10) + 10 = 2[(x+ 10) + 10]

3x+ 20 = 2x+ 40

x= 20.

Required ratio = (3x+ 10) : (x+ 10) = 70 : 30 = 7 : 3