$X$ is three times as old as $Y, Z$ was twice as old as $x$ four years ago. In the four year time, $x$ will be of $31$ years. What is the present age of $y$ and $z$ .

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The age of Sachin before y years was x years then his age after 4 years will be ______ years.

The correct option is C x+y+4Let the present age of Sachin be a years.∴ The age of Sachin before y years =(a−y) years=x years∴a−y=x⇒a=x+yHis age after 5 years will be=(a+4)years=(x+y+4)years.

The age of Sachin before $y$ years was $x$ years then his age after $4$ years will be ______ years.

The correct option is C $x + y + 4$
Let the present age of Sachin be $a$ years.

$∴$ The age of Sachin before $y$ years $= (a - y)$ years

$= x y e a r s$

$∴ a - y = x \Rightarrow a = x + y$

His age after $5$ years will be

$= (a + 4) y e a r s$

$= (x + y + 4) y e a r s$ .