Question

The age of the wood if only $1/16$ part of original $C^{14}$ is present in its piece is $(\frac{{}^{T}1}{2}of{C}^{14}is5,580years)$

• A. 5580
• B. 11,160
• C. 22320
• D. 16740

Answer 1

The correct option is C 22320

Given that half life, $t_{1/2}=5580years$

If activity in living tree was $N_0$ and presently in wood it is $N$ then

according to question $N=N_0/16$

Using the formula $N=N_0(\frac{1}{2}{)}^n$

and putting $N=N_0/16$ , we get $n=4$

where $n=\frac{time}{t_{1/2}}$

so time(age)=$n\times t_{1/2}=4\times 5580years=22320years$

Option C is correct.