Question

The age of the wood if only $\frac{1}{16}th$ part of original $C$${}^{14}$ is present in its piece is ($T$ of C${}^{14}$is $5,580$ years)

• A. $5580$ years
• B. $11,160$ years
• C. $22320$ years
• D. $16740$ years

Answer 1

Answer: (C)

$22320$ years

No of half lives $=x$

So, $\frac{1}{16}=(\frac{1}{2}{)}^x\Rightarrow x=4$

So, $4$ half lives

$\Rightarrow 4\times 5580=22320years$