The ages (in years) of 10 teachers in a school are
32, 44, 53, 47, 37, 54, 34, 36, 40, 50.
Find the median age.

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Solution

ANSWER:
Arranging the ages (in years) in ascending order, we have:
32, 34, 36, 37, 40, 44, 47, 50, 53, 54
Here, n is 10, which is an even number.
Thus, we have:

Median= Mean of 5th & 6th observations
$= \frac{37 + 54}{2}$
Hence, the median age is 42 years.

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Q. Following are the ages of 10 teachers in a school : 32, 41, 28, 54, 35, 26, 23, 33, 38 and 40
(i) The range of their ages is

Find the mean age from the following frequency distribution:
$\begin{matrix} Age (in years) & 25 - 29 & 30 - 34 & 35 - 39 & 40 - 44 & 45 - 49 & 50 - 54 & 55 - 59 Number of persons & 4 & 14 & 22 & 16 & 6 & 5 & 3 \end{matrix}$

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The ages (in years) of 10 teachers in a school are 32, 44, 53, 47, 37, 54, 34, 36, 40, 50. Find the median age.

ANSWER: Arranging the ages (in years) in ascending order, we have: 32, 34, 36, 37, 40, 44, 47, 50, 53, 54 Here, n is 10, which is an even number. Thus, we have: Median= Mean of 5th & 6th observations =37+542 Hence, the median age is 42 years.

The ages (in years) of 10 teachers in a school are
32, 44, 53, 47, 37, 54, 34, 36, 40, 50.
Find the median age.

ANSWER:
Arranging the ages (in years) in ascending order, we have:
32, 34, 36, 37, 40, 44, 47, 50, 53, 54
Here, n is 10, which is an even number.
Thus, we have:

Median= Mean of 5th & 6th observations
$= \frac{37 + 54}{2}$
Hence, the median age is 42 years.