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Standard VII
Mathematics
Applications (Word Problem)
The ages of A...
Question
The ages of A and B are in the ratio 8 : 3. Six years hence, their ages will be in the ratio 9 : 4. Find their present ages.
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Solution
Suppose that the present ages of A and B are 8x yrs and 3x yrs.
Then, (8x + 6) : (3x + 6) = 9 : 4
⇒
8
x
+
6
3
x
+
6
=
9
4
⇒ 32x + 24 = 27x + 54
⇒ 5x = 30
⇒ x = 6
Now, present age of A = 8
×
6 yrs = 48 yrs
Present age of B = 3
×
6 yrs = 18 yrs
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If the present ages of A and B are in the ratio 9 : 4 and seven years hence, the ratio of their ages will be 5 : 3, then find the their present ages.
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The ages of A and B are in the ratio 3 : 8. Six years hence, their ages will be in the ratio 4 : 9. The present age of A is
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