Question

The ages of teachers of a school are
$53,37,39,51,46,42,44,47,55,48$. Find the median

• A. $46.5$
• B. $47.5$
• C. $48.5$
• D. $49.5$

Answer 1

Answer: (A)

$46.5$

Age of teachers are: $53,37,39,51,46,42,44,47,55,48$
Arranging in ascending order: $37,39,42,44,46,47,48,51,53,55$
There are $10$ numbers, hence, the median will be the mean of $\frac{n}{2}$ and $\frac{n}{2}+1$ terms
Median $=$ mean of $5^{th}$ and $6^{th}$ terms
Median $=$ mean of $46$ and $47$
Median $=\frac{46+47}{2}$
Median $=\frac{93}{2}=46.5$