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Question

The air tight and smooth pistons of a cylindrical vessel are connected with a string as shown. Initially pressure and temperature of the gas are P and T. The atmospheric pressure is also P. At a later time, tension in the string is 38 PA, where A is the cross sectional area of the cylinder. At this time, the temperature of the gas has become

A
38T
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B
34T
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C
118T
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D
138T
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Solution

The correct option is C 118T
T + PA = PAT = (P P)A = 38PA (given)


P = 38P + P = 118P
Now volume is constant.
So, PT
Initially temperature is T0
Now as pressure has become 118P0, temperature will be 118T0

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