The algebra of an arithmetic sequence is 4n-1. Then the sequence is

1,3,7,11.....

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3,7,11,......

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1,4,8,12......

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4,8,12........

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Solution

The correct option is B
3,7,11,......

Given, 4n-1

If $n = 1 \Rightarrow 4 (1) - 1 = 3$

If $n = 2 \Rightarrow 4 (2) - 1 = 7$

If $n = 3 \Rightarrow 4 (3) - 1 = 11$

So the sequence is 3,7,11...

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The algebra of an arithmetic sequence is 4n-1. Then the sequence is

The correct option is B 3,7,11,...... Given, 4n-1 If n=1⇒4(1)−1=3 If n=2⇒4(2)−1=7 If n=3⇒4(3)−1=11 So the sequence is 3,7,11...

The correct option is B
3,7,11,......

Given, 4n-1

If $n = 1 \Rightarrow 4 (1) - 1 = 3$

If $n = 2 \Rightarrow 4 (2) - 1 = 7$

If $n = 3 \Rightarrow 4 (3) - 1 = 11$

So the sequence is 3,7,11...