The algebraic expression for sequence 1 + (1 + 5), 2 + (2 + 5), 3 + (3 + 5), ... is

n + (n + 5)

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n + (1 + 5)

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1 + (n + 5)

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n + (n + 1)

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Solution

The correct option is A
n + (n + 5)

n + (n + 5)

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Similar questions

Which of the following algebraic expressions explain the following

$\frac{1}{2}$ + $\frac{1}{3}$ = $\frac{5}{6}$

\frac{1}{5}, \frac{2}{5}, \frac{3}{5}, . . ., \frac{79}{5}

x^{2} + 2 y

x = 1

y = 1

tan ({sin}^{- 1} cos {tan}^{- 1} \frac{x}{2})

- \frac{2}{3}, - \frac{3}{5}, \frac{3}{5}, \frac{2}{3}

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