The alkene formed as a major product in the above elimination reaction is
[2006]

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C H_{2} = C H_{2}

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Solution

The correct option is B
Hofmann's rule: When theoretically more than one type of alkenes are possible in eliminations reaction, the alkene containing least alleviated double bond is formed as major product Hence

Note: It is less stearically $β$ - hydrogen is removed

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C H_{3} F C H C H_{2} C H_{2} C H_{3} C H_{3} O^{-} \to C H_{3} O H R (M a j o r P r o d u c t)

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