The alkene that will give the same product with HBr in the absence as well as in the presence of peroxide is?
A
2−butene
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B
1−butene
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C
propene
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D
1−hexene
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Solution
The correct option is C2−butene 2−butene is a symmetrical alkene so it gives the same product with HBr in the absence as well as in the presence of peroxide due to addition of Br at the same position (C=C bond) in accordance with markovnikov's rule in both the conditions that is in the absence as well as in the presence of peroxide.