Question

The allele for pea comb (P) in chickens in completely dominants to the allele for single comb(p). The alleles for black feather colour (B) and white feather colour (B) shows codominance, so that BB' individuals posses blue feathers. If chickens heterozygous for both pairs of gases are mated, what proportion of offspring are expected to be pea combed and white feathered?

• A. $9/16$
• B. $3/16$
• C. $1/16$
• D. $2/16$

Answer 1

The correct option is B $3/16$

Pea comb is dominant over single comb and black feather is codominant with white feather allele to produce bl

ue feather. The cross between BbPp X BbPp is solved in the Punnett square below. From there we can see, that the proportion of offspring expected to be pea combed and white feathered due to bbPp or bbPP genotype is 3/16.

So the correct option is '3/16'.

Male/ Female	BP	bP	Bp	bp
BP	BBPP	BbPP	BBPp	BbPp
bP	BbPP	bbPP	BbPp	bbPp
Bp	BBPp	BbPp	BBpp	Bbpp
bp	BbPp	bbPp	Bbpp	bbpp