The alternating current gain of a junction transistor in common base arrangement is 0.98. What is the change in the base current corresponding to a change of $5 m A$ in the emitter current and a change of $4.9 m A$ in the collector current?

0.1 m A

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0.2 m A

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0.3 m A

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0.4 m A

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Solution

The correct option is A $0.1 m A$
It is given that AC collector current $i_{C} = 4.9 m A$
and AC emitter current $i_{E} = 5 m A$
From Kirchoff's current law,
$i_{E} = i_{C} + i_{B}$
$⟹ i_{B} = i_{E} - i_{C} = 5 m A - 4.9 m A = 0.1 m A$

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