Question

The alternating emf applied and the current flowing in an $AC$ circuit are represented by $E=E_0\sin \omega t$ and $I_0\sin (\omega t+\frac{\pi }{2})$ respectively. The power loss in the circuit will be

• A. $zero$
• B. $\frac{E_0{I}_0}{2}$
• C. $\frac{E_0{I}_0}{\sqrt{2}}$
• D. $\frac{E_0{I}_0}{4}$

Answer 1

The correct option is A $zero$

Current $=I_0\sin (\omega t+\frac{\pi }{2})=I_0\cos \left(\omega t\right)$

Power loss $=E_0\sin \left(\omega t\right)\times I_0\cos \left(\omega t\right)=0$