The altitude AD of ΔABC, in which ∠A is obtuse and AD = 10 cm, if BD = 10 cm and CD = 10√3 cm, then ∠A =

110^o

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100^o

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105^o

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115^o

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Solution

The correct option is C
105^o

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Similar questions

The altitude AD of a ΔABC, in which ∠A is obtuse and AD = 10cm. If BD = 10√3cm, then ∠A = ?

The altitude AD of in $Δ$ ABC is 10 cm. The $∠$ A is an obtuse angle and BD = 10 cm, CD = 10 $\sqrt{3}$ cm. Find $∠$ A.

Δ A B C

∠ A

10 \sqrt{3}

∠ A

In ∆ABC, AD is bisector of ∠A and AD meets BC at D. If AB = 5cm, BD = 2cm, CD = 3cm. Then AC is equal to.

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