The altitude and the base of atringular field are in the ratio 6:5. If its cost is 4957200 at the rate of 36720 per hectare and 1 hectare =10000sq. M find dimensions of the field

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Q. The altitude and the base of a triangular field are in the ratio 6:5. If its cost is ₹ 49,57,200 at the rate of ₹ 36,720 per hectare and 1 hectare = 10,000 square meter, find (in meter) dimensions of the field.

The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is Rs 49,57,200 at the rate of Rs 36,720 per hectare and 1 hectare =10,000 sq. m, find (in metre) dimensions of the field.

Area of the given triangular field $= \frac{C o s t o f t h e f i e l d}{R a t e} = \frac{49, 57, 200}{36, 720}$ hectare

=135 hectare

$= 135 \times 10, 000$ sq. m=1350000 $m^{2} .$

Q. The altitude and the base of a triangular field are in the ratio

6 : 5

. If ploughing cost of field is Rs

49, 57, 200

at the rate of Rs

36, 720

per hectare and

1

hectare

= 10, 000

sq. m, find altitude (in metre)

The base of a triangular field is three times its altitude. If the cost of sowing seeds in the field at 58/- per hectare is 783/-,find base and altitude.

Q. The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs 24.60 per hectare is Rs 332. 10, find its base and height.

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