The amine formed from an amide by means of bromine and alkali has

Same number of C atoms as that of amide

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One less C atom than that of amide

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One more C atom than that of amide

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Two more C atoms than that of amide

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Solution

The correct option is B One less C atom than that of amide

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Similar questions

Q. The reagent that converts a

1^{\circ}

amide to a

1^{\circ}

amine without changing the number of C atom is

Q. Write and name the reaction to prepare amine containing less number of carbon atoms from acid-amide.

The Conversion of an amide by action of NaOH and $B r_{2}$ to primary amine that has one carbon less than the starting amide is known as Hofmann-Bromamide reaction.

$R - O | | C - N H_{2} B r_{2} + N a O H - ------ \to (o r) N a o B r R - N H_{2} + N a B r + N a_{2} C O_{3}$

Q. Assertion :In Hofmann bromide reaction, the amine formed has one carbon atom less than the parent

1^{o}

amide. Reason: N-methyl acetamide undergoes Hofimann bromamide reaction.

The Conversion of an amide by action of NaOH and $B r_{2}$ to primary amine that has one carbon less than the starting amide is known as Hofmann-Bromamide reaction.

$R - O | | C - N H_{2} B r_{2} + N a O H - ------ \to (o r) N a o B r R - N H_{2} + N a B r + N a_{2} C O_{3}$

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