The amine which reacts with p-toluenesulfonyl chloride to give a clear solution which on acidification gives insoluble compound is:

C_{2} H_{5} N H_{2}

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(C_{2} H_{5})_{2} N H

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(C_{2} H_{5})_{3} N

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C H_{3} N H C_{2} H_{5}

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Solution

The correct option is A $C_{2} H_{5} N H_{2}$
The amine which reacts with p-toluenesulphonyl chloride to give a clear solution which on acidification gives insoluble compound is a primary amine such as ethyl amine $C_{2} H_{5} N H_{2}$ .

$C_{2} H_{5} N H_{2} + C H_{3} - C_{6} H_{4} - S O_{2} - C l O H^{-} - -- \to C H_{3} - C_{6} H_{4} - S O_{2} - N H C_{2} H_{5} K O H - -- \to C H_{3} - C_{6} H_{4} - S O_{2} - N^{-} C_{2} H_{5} K^{+} H^{+} - - \to C H_{3} - C_{6} H_{4} - S O_{2} - N H C_{2} H_{5}$ .

It is Hinsberg's test used to distinguish between primary, secondary and tertiary amine.

Option A is correct.

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