Question

The ammeter reading in the circuit below is

• A. $2$ $A$
• B. $3$ $A$
• C. $6$ $A$
• D. $5$ $A$

Answer 1

The correct option is C $6$ $A$

As we know, in parallel connection all the voltages are equal.

$\Rightarrow$ Voltage in each of the three branches will be equal.

$2I_1=1I_2=3I_2=V\left(say\right)\to \left(1\right)$ where, $V=$ equal voltage

Also we know, by KCL

$I_1+I_2+I_3=11\to \left(2\right)$

Solving equation $\left(1\right)$ & $\left(2\right)$

$\frac{V}{2}+V+\frac{V}{3}=11$

$\frac{11V}{6}=11$

$V=6$

Thus, we find that

$I_1=\frac{6}{2}$

$\Rightarrow I_1=3A$

$I_2=\frac{6}{1}\Rightarrow I_2=6A$ $\to$ Reading of Ammeter

$I_3=\frac{6}{3}\Rightarrow I_3=2A$.