The ammonia (NH3) released on quantitative reaction of 0.6 g urea (NH2CONH2) with sodium hydroxide NaOH can be neutralized by:
A
200 mL of 0.2NHCl
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B
100 mL of 0.1NHCl
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C
200 mL of 0.4NHCl
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D
100 mL of 0.2NHCl
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Solution
The correct option is D 100 mL of 0.2NHCl Moles of urea =(0.660=0.01) NH2CONH20.01+2NaOH→Na2CO3+2NH30.02 0.02 moles of NH3 reacts with 0.02 moles of HCl. Moles of HCl in option a =0.2×1001000=0.02