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Question

The ammonia (NH3) released on quantitative reaction of 0.6 g urea (NH2CONH2) with sodium hydroxide NaOH can be neutralized by:

A
200 mL of 0.2 N HCl
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B
100 mL of 0.1 N HCl
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C
200 mL of 0.4 N HCl
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D
100 mL of 0.2 N HCl
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Solution

The correct option is D 100 mL of 0.2 N HCl
Moles of urea =(0.660=0.01)
NH2CONH20.01+2NaOHNa2CO3+2NH30.02
0.02 moles of NH3 reacts with 0.02 moles of HCl.
Moles of HCl in option a =0.2×1001000=0.02

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