The amount in parts by weight of sulphur present in one sulphuric acid molecule:

16

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32

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64

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48

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Solution

The correct option is A $32$
$H_{2} S O_{4}$ is sulphuric acid.
Molecular mass of $H_{2} S O_{4} = 2 + 32 + (4 \times 16) = 38 g$
Weight of sulphur in it $= 32 g$
So, amount in parts by weight of sulphur in one sulphuric acid molecule is $32 g$

Suggest Corrections

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