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Hydroponics

The amount of...

Question

The amount of BaSo4 formed upon mixing 100ml of 20.8% Bacl2 solution with 50ml of 9.8% H2So4 solution will be

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50 m l

B a C l_{2}

100 m l

H_{2} S O_{4}

B a S O_{4}

[B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l]

B a S O_{4}

100

20.8 %

B a C l_{2}

50

9.8 %

H_{2} S O_{4}

= 137

= 35.5

= 32

= 1

= 16

B a S O_{4}

100

20.8 %

B a C l_{2}

50

9.8 %

H_{2} S O_{4}

B a = 137, C l = 35.5, S = 32, H = 1

O = 16

B a C l_{2}

H_{2} S O_{4}

B a S O_{4}

(B a = 137, C l = 35.5, S = 32, H = 1, O = 16)

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l

{BaCl}_{2}

H_{2} {SO}_{4}

{BaSO}_{4}

[{BaCl}_{2} {+ H}_{2} {SO}_{4} \to {BaSO}_{4} + 2HCl]

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