The amount of charge $Q$ passed in time $t$ through a cross-section of wire is $Q = 5 t^{2} + 3 t + 1.$
The value of current at time $t = 5$ is

9 A

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49 A

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53 A

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Solution

The correct option is C $53 A$
$I = \frac{d Q}{d t} = 10 t + 3$

At $t = 5 s, I = 10 \times 5 + 3 = 53 A$

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The amount of charge Q passed in time t through a cross-section of wire is Q=5t2+3t+1.The value of current at time t=5 is

The correct option is C 53 AI=dQdt=10t+3At t=5s,I=10×5+3=53A

The amount of charge $Q$ passed in time $t$ through a cross-section of wire is $Q = 5 t^{2} + 3 t + 1.$
The value of current at time $t = 5$ is

The correct option is C $53 A$
$I = \frac{d Q}{d t} = 10 t + 3$

At $t = 5 s, I = 10 \times 5 + 3 = 53 A$