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Question

The amount of electricity which releases 2.0g of gold from a gold salt is the same as that which dissolves 0.967g of copper anode during the electrolysis of copper sulphate solution. What is the oxidation number of gold in the gold state? (At. Wt. of Cu = 63.5; Au = 197)

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Solution

The number of moles of copper is 0.96763.5=0.015 moles.
The number of moles of gold is 2.0197=0.01 moles.
The oxidation number of copper is 2. Let x be the oxidation number of gold.

0.015×2=0.01×x
x=0.0300.010=3.
Hence, the oxidation number of gold is 3.

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