Question

The amount of energy relased when ${10}^o$ atoms of iodine in vapour state are converted to $I^{-}$ ions is $4.9\times {10}^{-13}J$. What is the electron affinity of iodine in eV per atom?

• A. $2.0$
• B. $2.5$
• C. $2.75$
• D. $30.6$

Answer 1

The correct option is D $30.6$

$I+e^{-}\to I^{-},E.A=4.9\times {10}^{-18}J.$

$\therefore E.A\left(eV\right)=\left(\frac{4.9\times {10}^{-18}}{1.602\times {10}^{-19}}\right)=\left(\frac{4.9\times 10}{1.6}\right)=30.6eV$