The amount of energy required to convert 5 moles of sodium atoms in the gaseous state to sodium ions is x - 106 J- Find x to the nearest possible integer- Ionisation enthalpy of Na-5-1 eV-atom-

The ionisation enthalpy of sodium = 5.1 eV/atom = 5.1× 6.023× 10^23 eV/mol =5.1× 6.023 × 10^23 nbsp; × 1.6× 10^ 19 J/mol =491.47 kJ/mol Energy required to co ...

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Standard XII

Chemistry

Ionization Enthalpy

The amount of...

Question

The amount of energy required to convert 5 moles of sodium atoms in the gaseous state to sodium ions is $x \times 10^{6} J$ . Find $x$ to the nearest possible integer. Ionisation enthalpy of $Na = 5.1 eV/atom$ .

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Solution

The ionisation enthalpy of sodium = 5.1 eV/atom
$= 5.1 \times 6.023 \times 10^{23} e V / m o l$
$= 5.1 \times 6.023 \times 10^{23} \times 1.6 \times 10^{- 19} J / m o l$
$= 491.47 k J / m o l$
Energy required to convert 5 moles of sodium,
$= 5 \times 491.47 k J = 2.45 \times 10^{6} J$

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The amount of energy required to convert 5 moles of sodium atoms in the gaseous state to sodium ions is x×106 J. Find x to the nearest possible integer. Ionisation enthalpy of Na=5.1 eV/atom.

The ionisation enthalpy of sodium = 5.1 eV/atom =5.1×6.023×1023eV/mol =5.1×6.023×1023×1.6×10−19J/mol =491.47 kJ/mol Energy required to convert 5 moles of sodium, =5×491.47 kJ=2.45×106J

The amount of energy required to convert 5 moles of sodium atoms in the gaseous state to sodium ions is $x \times 10^{6} J$ . Find $x$ to the nearest possible integer. Ionisation enthalpy of $Na = 5.1 eV/atom$ .

The ionisation enthalpy of sodium = 5.1 eV/atom
$= 5.1 \times 6.023 \times 10^{23} e V / m o l$
$= 5.1 \times 6.023 \times 10^{23} \times 1.6 \times 10^{- 19} J / m o l$
$= 491.47 k J / m o l$
Energy required to convert 5 moles of sodium,
$= 5 \times 491.47 k J = 2.45 \times 10^{6} J$