The amount of energy required to remove an electron from ground sate of $H e^{+}$ ion is:

- 54.4

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- 13.6

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- 24.4

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- 34

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Solution

The correct option is C $- 54.4$ eV
The $H e^{+}$ ion is just like a hydrogen atom with two units of charge in the nucleus. Since the hydrogenic energy levels depend upon the square of the nuclear charge, the energy of the remaining helium electron should be just $4 \times (- 13.6 e V) = - 54.4$ eV as observed.

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The amount of energy required to remove an electron from ground sate of He+ ion is:

The correct option is C −54.4 eVThe He+ ion is just like a hydrogen atom with two units of charge in the nucleus. Since the hydrogenic energy levels depend upon the square of the nuclear charge, the energy of the remaining helium electron should be just 4×(−13.6eV)=−54.4 eV as observed.

The amount of energy required to remove an electron from ground sate of $H e^{+}$ ion is: