Question

The amount of $H_2{O}_2$ present in $1L$ of $1.5N$ $H_2{O}_2$ solution is_____________.

• A. $2.5g$
• B. $25.5g$
• C. $3.0$
• D. $8.0$

Answer 1

The correct option is B $25.5g$

valency-factor of $H_2{O}_2,\left(n\right)=2$

As we know that

$Normality=Molarity\times n$,

Given that:-

$Normality=1.5N$

$Volume=1L$

$\therefore$ Molarity of $H_2{O}_2=\frac{1.5}{2}=0.75M$

$\therefore$ moles of $H_2{O}_2$ required for 1 L $=0.75M\times 1L=0.75mol$

Molecular weight of $H_2{O}_2=34g{mol}^{-1}$

$\therefore$ weight of $H_2{O}_2$ required $=0.75\times 34=25.5g$