Question

The amount of $H_2{O}_2$ present in 1L of 1.5 N $H_2{O}_2$ is ?

Answer 1

Molar mass H2O2H_2O_2H2​O2​ = 2+32 = 34g/mol

Equivalent weight of $H_2{O}_2$ = $\frac{Molarmass}{n-factor}$

n-factor for $H_2{O}_2$ = 2

Equivalent weight of $H_2{O}_2$ = $\frac{34}{2}=17\frac{g}{mol}$

$Normality=\frac{mass}{equivalentweight}\times \frac{1}{v\left(lit\right)}$

$1.5=\frac{mass}{17}\times \frac{1}{1}$

$mass=25.5g$