The amount of heat energy required to raise the temperature of 1 g of Helium at NTP- from T 1 K to T 2 K isA- 3-4 N a k B T 2- T 1B- 3-8 N a k B T 2- T 1C- 3-2 N a k B T 2- T 1D- 3-4 N a k B T 2- T 1

The correct option is B 3/8N_a k_B (T_2 T_1) Number of moles in 1g He =1/4 Amount of heat energy required to raise its temepratre from T_1 K to T_2 K =_nC_v ...

Heat Capacity at Constant Volume

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Question

The amount of heat energy required to raise the temperature of 1g of Helium at NTP, from $T_{1}$ K to $T_{2}$ K is

\frac{3}{4} N_{a} k_{B} (\frac{T_{2}}{T_{1}})

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\frac{3}{8} N_{a} k_{B} (T_{2} - T_{1})

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\frac{3}{2} N_{a} k_{B} (T_{2} - T_{1})

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\frac{3}{4} N_{a} k_{B} (T_{2} - T_{1})

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Solution

The correct option is B $\frac{3}{8} N_{a} k_{B} (T_{2} - T_{1})$

Number of moles in 1g He = $\frac{1}{4}$
Amount of heat energy required to raise its temepratre from $T_{1} K$ to $T_{2} K$
$=_{n} C_{v} Δ T = (\frac{1}{4}) (\frac{3}{2} R) (T_{2} - T_{1}) = \frac{3}{8} k_{B} N_{A} (T_{2} - T_{1})$

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The amount of heat energy required to raise the temperature of 1g of Helium at NTP, from T1 K to T2 K is

The correct option is B 38NakB(T2−T1) Number of moles in 1g He =14 Amount of heat energy required to raise its temepratre from T1K to T2K =nCvΔT=(14)(32R)(T2−T1)=38kBNA(T2−T1)

The amount of heat energy required to raise the temperature of 1g of Helium at NTP, from $T_{1}$ K to $T_{2}$ K is

The correct option is B $\frac{3}{8} N_{a} k_{B} (T_{2} - T_{1})$

Number of moles in 1g He = $\frac{1}{4}$
Amount of heat energy required to raise its temepratre from $T_{1} K$ to $T_{2} K$
$=_{n} C_{v} Δ T = (\frac{1}{4}) (\frac{3}{2} R) (T_{2} - T_{1}) = \frac{3}{8} k_{B} N_{A} (T_{2} - T_{1})$