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Question

The amount of heat needed to melt 2 kg of ice at its melting point, when latent heat of ice is 80 cal/g, is _____.
(1 cal=4.184 J)

A
40×105 J
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B
6.7×105 J
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C
3.35×105 J
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D
1.675×105 J
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Solution

The correct option is B 6.7×105 J
Latent heat of ice is defined as the amount of heat needed to convert 1g of ice into water. As given in the question, its value is 80 cal/g.

Since 1 cal=4.184 J
80 cal/g=80×4.184 J/g
=334.72 J/g

Heat needed to melt 2 kg of ice is:
Heat = mass × latent heat of ice
=2×334.72 kJ
=669.44 kJ
=669.44×103J=6.7×105 J

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