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Byju's Answer
Standard IX
Physics
Specific Heat Capacity
The amount of...
Question
The amount of heat required to convert 5 gm of ice at
−
20
0
C
to water at
100
0
C
is
A
450
cal
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B
950
cal
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C
100
cal
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D
none of these
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Solution
The correct option is
B
950
cal
Heat supply
=
Q
i
c
e
−
20
→
0
+
Q
i
c
e
→
w
a
t
e
r
+
Q
w
a
t
e
r
0
→
100
Heat
=
m
s
i
c
e
(
0
−
(
−
20
)
)
+
m
l
f
+
m
s
w
a
t
e
r
(
100
−
0
)
=
5
×
1
2
×
20
+
5
×
80
+
5
×
1
×
100
=
50
+
400
+
500
=
950
cal.
Suggest Corrections
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