The amount of heat required to raise the temperature of 1 mole of a diatomic gas by 1- C at constant pressure is 7 cal- The amount of heat which goes as internal energy of the gas is nearly-A- 5 calB- 2 calC- 3 calD- 2-5 cal

The correct option is A 5 calFor a diatomic gas, nbsp; C_p=7/2R C_v=5/2R ⇒C_p/C_v=7/5 Given C_p=7 cal ⇒ C_v=5/7×7=5 cal The amount of heat which goes as inte ...

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Standard XII

Chemistry

Relation between Cp and Cv

The amount of...

Question

The amount of heat required to raise the temperature of 1 mole of a diatomic gas by $1^{\circ} C$ at constant pressure is 7 cal. The amount of heat which goes as internal energy of the gas is nearly:

3 cal

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2.5 cal

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5 cal

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2 cal

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Solution

The correct option is C 5 cal
For a diatomic gas,
$C_{p} = \frac{7}{2} R$
$C_{v} = \frac{5}{2} R$
$\Rightarrow \frac{C_{p}}{C_{v}} = \frac{7}{5}$
Given $C_{p} = 7 c a l$
$\Rightarrow C_{v} = \frac{5}{7} \times 7 = 5 c a l$
The amount of heat which goes as internal energy is 5 cal.
( $Δ U = C_{v} Δ T = 5 \times 1 = 5 c a l$ )

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