The amount of heat required to raise the temperature of $100 g$ water from $20^{o} C$ to $40^{o} C$ will be

0

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100 c a l

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2000 c a l

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4000 c a l

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Solution

The correct option is C $2000 c a l$
We have specific heat of water as $C = 1 c a l / g K$ .
Amount of heat required is given as $m C Δ T = 100 \times 1 \times (40 - 20) = 2000 c a l$

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