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Byju's Answer

Standard XII

Chemistry

Enthalpy

The amount of...

Question

The amount of heat required to raise the temperature of $75 g$ of ice at $0^{o} C$ to water at $10^{o} C$ is:
[latent heat of fusion of ice is $80 c a l / g$ , specific heat of water is $1 c a l / g^{o} C$ ]

750 k c a l

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6.75 \times 10^{3} k c a l

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60 \times 10^{3} k c a l

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6.75 k c a l

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Solution

The correct option is D $6.75 k c a l$
$Q = m L_{f} + m C Δ T$

$\Rightarrow Q = 75 (80 + 1 \times 10) = 6.75 \times 10^{3} c a l = 6.75 k c a l$

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Similar questions

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The amount of heat required to raise the temperature of 75 g of ice at 0oC to water at 10oC is: [latent heat of fusion of ice is 80 cal/g, specific heat of water is 1 cal/goC]

The correct option is D 6.75 kcalQ=mLf+mCΔT⇒Q=75(80+1×10)=6.75×103 cal=6.75 kcal

The amount of heat required to raise the temperature of $75 g$ of ice at $0^{o} C$ to water at $10^{o} C$ is:
[latent heat of fusion of ice is $80 c a l / g$ , specific heat of water is $1 c a l / g^{o} C$ ]

The correct option is D $6.75 k c a l$
$Q = m L_{f} + m C Δ T$

$\Rightarrow Q = 75 (80 + 1 \times 10) = 6.75 \times 10^{3} c a l = 6.75 k c a l$