The amount of liquid flowing per second in the tubes (1),(2) and (3) are 10m3/s,5m3/s and 8m3/s respectively. The velocity of liquid in the tube (4) having cross - section of 0.5m2 is
A
7m/s
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B
14m/s
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C
3.5m/s
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D
12m/s
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Solution
The correct option is B14m/s It is clear that unit of Av is m3s−1, where A is area of cross -section and v is the speed of flow
Applying the equation of continuity at O and assuming the liquid is leaving O in tube 4 with speed v. A1V1+A3V3=A2V2+A4V4 10+5=8+0.5v ⇒v=14ms−1.