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Question

The amount of liquid flowing per second in the tubes (1),(2) and (3) are 10 m3/s,5 m3/s and 8 m3/s respectively. The velocity of liquid in the tube (4) having cross - section of 0.5 m2 is

A
7 m/s
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B
14 m/s
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C
3.5 m/s
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D
12 m/s
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Solution

The correct option is B 14 m/s
It is clear that unit of Av is m3s1, where A is area of cross -section and v is the speed of flow

Applying the equation of continuity at O and assuming the liquid is leaving O in tube 4 with speed v.
A1V1+A3V3=A2V2+A4V4
10+5=8+0.5v
v=14 ms1.

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