Question

The amount of $Mg$ required to replace $Ag$ from $500mlof0.5MAgN{O}_3$, solution is:

• A. $1.2g$
• B. $2.4g$
• C. $6g$
• D. $4.8g$

Answer 1

The correct option is D $4.8g$

The equation for the reaction can be written as:
$Mg+2AgN{O}_3\to Mg(N{O}_3{)}_2+2Ag$
$\therefore$ 216 g ($108g\times 2$) of $Ag$ is displaced by = $24g$ of $Mg$

For 500ml, the amount of $Ag$ will be 42.5g
Thus, $42.5g$ of $Ag$ is displaced by = $\frac{24}{216}\times 42.5$ = $4.8g$ of Mg