The amount of money in the account every year, when $R s 10000$ is deposited at compound interset at $8 %$ per annum.

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Solution

Given Amount $= R s 10, 000$
interest $= 8 %$
Total amount $= P (1 + r)^{n}$
$P$ is principle amount
$r$ is the rate of interest
$n$ is no of year
Compound interest increases depend on principle

Next year interest is interest on before year total
$= 10000 (1 + 0.08)^{n}$
At the end of the first year, $= 1000 (1.08) = 10800 / -$
Every year the amount increases at $1.08$ times

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The amount of money in the account every year, when Rs10000 is deposited at compound interset at 8% per annum.

The amount of money in the account every year, when $R s 10000$ is deposited at compound interset at $8 %$ per annum.